Question

In a 0.2 molal aqueous solution of a weak acid hx, the degree of ionisation is 0.3. Taking kf for water as 1.85 k kg mol-1, the freezing point of the solution will be nearest to:

Answer 1

i = 1+( n-1)0.3

=1+(2-1)0.3

=1+0.3=1.3

del Tf = i Kf molality

= 1.3 X 1.85 X 0.2 = 0.481

Freeing point of solvent - freezing Point of. solution. =0.481

O - Tf solution =0.481

freezing point of solution =-0.481