Question

In a 0.2 molar aqueous solution of a weak acid hx the degree of ionisation is 0.3,what is the feezing point of the soln​

Answer 1

0.2 molal

i = 1+( n-1)alpha

I =1+(2-1)0.3

i =1+0.3=1.3

Del Tf =i x Kf X molality

=1.3x1.86x0.2 = 0.4836

freezing point solution = -0.4836 celsius

Answer 2

Answer:

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