In a 1 km race, a beats b by 200 m and c by 360 m. in a race of 500 m, by how many metres would b beat c?
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HALF OF 1 KM = 500 M
HENCE HALF ALL THE TERMS
IN 500M
A BEATS B BY 100M AND C BY 180
HENCE HALF ALL THE TERMS
IN 500M
A BEATS B BY 100M AND C BY 180
Answered by
0
Given:
Total distance in the race=500m
To find:
The number of metres by which B beats C.
Solution:
B wins over C by 100m.
We are given that the total distance to be covered during the race of A, B, C is 1km or 1000m.
Also, A beats C by 360m and B by 200m.
So, when A completes the 1000m, the meters run by C and B is as follows-
B's distance=1000-200=800m
C's distance=1000-360=640m
Now, the ratio of the meters run by B and C=800:640
=10:8
In B and C's race, let C covers X metres.
So, B's distance=500m
C's distance=X
The ratio of their distances=10:8
On equating,
500:X=10:8
500×8/10=X
50×8=X
400=X
So, B wins over C by (500-X)m.
=500-400
=100m
Therefore, B wins over C by 100m.
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