In a 100 m race, Abhay runs at a speed of 2m/s. If he gives Rohan a start of 5 m and still beats him by 10 seconds, find the speed of Rohan.
Answers
Answer:
Recall:
\text{Distance } = \text{Speed } \times \text{Time }Distance =Speed ×Time
\text{Time } = \text{Distance } \div \text{Speed }Time =Distance ÷Speed
\text {Speed } = \text {Distance } \div \text {Time }Speed =Distance ÷Time
Given:
\text{Distance } = 100 \text{ m}Distance =100 m
Find the time taken by Abhay:
\text{Speed } = 2 \text{ m/s}Speed =2 m/s
\text{Time } = \text{Distance } \div \text{Speed }Time =Distance ÷Speed
\text{Time } = 100 \div 2Time =100÷2
\text{Time } = 50 \text{ seconds}Time =50 seconds
Find the distance that Rohan need to run:
\text {Distance } = 100 - 5Distance =100−5
\text {Distance } = 95 \text { m}Distance =95 m
Find the time taken by Rohan:
\text {Time Taken } = 50 + 10Time Taken =50+10
\text {Time Taken } = 60 \text { seconds}Time Taken =60 seconds
Find Rohan's speed:
\text {Speed } = \text {Distance } \div \text {Time }Speed =Distance ÷Time
\text {Speed } = 95 \div 60Speed =95÷60
\text {Speed } = 1.58 \text { m/s}Speed =1.58 m/s
Answer: Rohan ran at a speed of 1.58 m/s
