Math, asked by Madhav9508, 1 year ago

In a 100 m race, partham can beat ishan by 20 m and ishan can beat sarthak by 10 m. In the same race, partham can beat sarthak by:

Answers

Answered by nidhilan
10
by 30 metres
hope this helps you
please verify the answer before using it :-):-)
Answered by MavisRee
14

Answer:


Partham can beat Sarthak by 28 m

Step-by-step explanation:

Given

Total length of race = 100m

According to question,

Partham can beat ishan by 20 m

So if,

Parthm run 100 m, ishan will run 80 m.

Distance ratio of partham : ishan = 100 : 80 = 5 : 4

Also, it is mentioned

ishan can beat sarthak by 10 m.

That is

When ishan Run 100m, sarthak will run 90 m.

Now

Distance ration of Ishan : Sarthak = 100 : 90 = 10 : 9


Now Partham : Sarthak = Partham : Ishan * Ishan : Sarthak


= 5/4 * 10/9 = 25/18

Multiplying both numerator and denominator by 4

now Partham : Sarthak = 25*4 / 18*4= 100 / 72

So

when Partham run 100m, Sarthak will run 72 , That means,

Partham will beat Sarthak by =

(100-72) = 28 m.

Hence,

Partham can beat Sarthak by 28 m

Similar questions