In a 100 m race, partham can beat ishan by 20 m and ishan can beat sarthak by 10 m. In the same race, partham can beat sarthak by:
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Answered by
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by 30 metres
hope this helps you
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hope this helps you
please verify the answer before using it :-):-)
Answered by
14
Answer:
Partham can beat Sarthak by 28 m
Step-by-step explanation:
Given
Total length of race = 100m
According to question,
Partham can beat ishan by 20 m
So if,
Parthm run 100 m, ishan will run 80 m.
Distance ratio of partham : ishan = 100 : 80 = 5 : 4
Also, it is mentioned
ishan can beat sarthak by 10 m.
That is
When ishan Run 100m, sarthak will run 90 m.
Now
Distance ration of Ishan : Sarthak = 100 : 90 = 10 : 9
Now Partham : Sarthak = Partham : Ishan * Ishan : Sarthak
= 5/4 * 10/9 = 25/18
Multiplying both numerator and denominator by 4
now Partham : Sarthak = 25*4 / 18*4= 100 / 72
So
when Partham run 100m, Sarthak will run 72 , That means,
Partham will beat Sarthak by =
(100-72) = 28 m.
Hence,
Partham can beat Sarthak by 28 m
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