Question

In a 100 meters running race, if a defeats b in 10meters and defeats c in 28 meters, then in how many meters b defeats c?

Answer 1

Answer:

Hence, b defeats c in=90-72=18 meters.

Step-by-step explanation:

In a 100 meters race a defeats b by 10 meters

This means when a covers 100 meters b covers 90 meters.

so, the distance ratio of a and b is given as:

a:b=100:90

Also a defeats c in 28 meters.

i.e. when a covers 100 meters then c covers 72 meters.

hence the distance ratio of a and c is given as:

a:c=100:72

Hence, a:b:c=100:90:72

Hence, b defeats c in=90-72=18 meters.