Math, asked by devildesai200pb4oxs, 1 year ago

in a 100 race A gives B a head start and he beat B by 10 m or 3 second than the speed of A

Answers

Answered by sammujadhav
0
A takes 100/10 = 10 seconds to complte the race

so B will take 10 + 1.25 = 11.25sec to complete 90M as B has a head start of 10M to A

so B will take 100 * 11.25 / 90 = 12.5 Seconds

ANS = 12.5 Sec

devildesai200pb4oxs: read question carefully
sammujadhav: what's wrong with it
Similar questions