Question

In a 155ml homogeneous mixture of liquor, water and soda, the concentration of liquor is highest and that of soda is least. Quantities (in ml) of soda, water and liquor, which are integers, are in a geometric progression, in the given order. 31 ml of solution is withdrawn and replaced with liquor. Now, again 31 ml of solution is withdrawn and replaced with water. What additional amount of water should be mixed to the solution such that concentration of water becomes 40%

Answer 1

Answer:

A solution of alcohol in water has been prepared by mixing 150ml of alcohol with 600 ml of water. Calculate th… Get the answers you need, ...

Explanation:

Answer 2

Answer:

25ml

Explanation:

The trick is knowing the initial volumes:

155ml --> 5ml , 25ml, 125ml

That's it

Now we see we are replacing 31ml from the 155ml solution that is 20%

Initial vols --> 5 , 25 , 125

after first replacement --> 4 , 20, 131

after second replacement -->  xx.xx, 47, xx.xx ( i didnt calculate for the others because i know the total vol will be 155ml)

so 47+25/155+25 = 40%