Question

In |_A=2|_B=3|_C Find |_A, |_B, |_C​

Answer 1

Answer:

98112)°,(49111)° and (32118)°

Step-by-step explanation:

Given triangle ABC

∠A=2∠B=3∠C 

Let ∠A=x

then ∠B=2x

∠C=3x

we know that sum of angles in a triangle = 160°

∠A+∠B+∠C=180°x+2x+3x=180°66x+3x+2x=180°11x=180×6∠A=x=(98112)°∠B=2x=(49111)°∠C=3x=(32118)°

angles are (98112)°,(49111)° and (32118)