Math, asked by madhusingh42127, 9 months ago

In a 2 digit number, ten's digit is twice the unit digit.If the difference of the number obtained by reversing the digits and the original number is 18,find the number.​

Answers

Answered by aditya12515k37
11

Answer:

Answer is 2.

Step-by-step explanation:

Take unit digit be x and ten's digit be 2x.

2x is in ten's place so it can be written like 2x*10 that is 20x.

So 20x+x is the first number.

Now on reversing this it would be x and 2x.

And x is in ten's place so it can be written as x*10 that is 10x.

So 10x+2x is second number.

Now difference between them is 18.

So expression can be written like this

(20x+x) - (10x+2x)=18

(21x) - (12x)=18

21x - 12x=18

9x=18

x=2.

So numbers are 42 and 24.

I hope this helps you

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