Question

In a 2-digit number, the 10s digit is 1 more than 2 times the unit digit and their sum is 36 less than the number formed by reversing the digits. Find the number.


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Answer 1

Answer:

Let 10s digit is x & unit digit is y.

a/q

$x = 2y + 1 \\ x - 2y = 1.......(i)$

now,

$10x + y - 36 = 10y + x \\9x - 9y = 36 \\ x - y = 4.....(ii)$

Apply (ii) – (i)

$(x - y) - (x - 2y) = 4 - 1 = 3 \\ y = 3$

putting the value of y in (ii),

$x - 3 = 4 \\ x = 7$

so number is 10x+y = 10×7 + 3 = 73

Ans.