Question

In a 2-digit number, the digits in the tens place is three times the digit in the ones place and sum of the
digits is equal to 12. Find the number.​

Answer 1

Answer:

the number is 39

Step-by-step explanation:

Let number be 'xy'

if ones place digit is 3 times the number in the ten's place. then

y = 3x

therefore,

x + 3x = 12

4x = 12

x = 3

Hence, one's place digit = 3

             ten's place digit = 9

to sum up,

39

Answer 2

The required number is 93.

Given:

In a 2-digit number, the digits in the tens place are three times the digit in the one's place and the sum of the digits is equal to 12.

To Find:

The required number.

Solution:

Let us assume that the one's place of the two-digit number is occupied by 'y' and the ten's place is occupied by 'x'.

Hence the required number = 10x + y.

According to our given condition, the digits in the tens place are three times the digit in the one's place. Writing this statement in terms of an equation, we have:

x = 3y .......................(I)

Also, we have been given that the sum of the digits is equal to 12. Writing this statement in terms of an equation, we have:

x + y = 12 .......................(II)

On substituting the value of equation (I) in (II) we have:

3y + y = 12

⇒ 4y = 12

⇒ y = 12/4 = 3

By putting the value of y in equation (I), we have:

x = 3y

⇒ x = 3(3) = 9

Hence, x = 9 and y = 3

So the required number is 10x + y = 10(9) + 3 = 93.

∴ The required number is 93.

#SPJ3