In a 2- digit number, the unit digit is four times the tens digit and the sum of the digit 10 the find the number
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Answered by
4
Let the tens place digit be a
Unit place digit = 4a
According to question
a+4a = 10
=> 5a = 10
a= 2
Tens place digit = 2
Unit place digit = 8
No. = 10*2+8
= 28
Hope it will help you
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Unit place digit = 4a
According to question
a+4a = 10
=> 5a = 10
a= 2
Tens place digit = 2
Unit place digit = 8
No. = 10*2+8
= 28
Hope it will help you
Please mark as brainliest if you liked the solution
Answered by
3
Your answer is here
x+4x=10
5x=10
x=10/5
x=2
tens digit =x
=2
ones digit=4(x)=4(2)=8
2+8=10
hence 28 is the number
x+4x=10
5x=10
x=10/5
x=2
tens digit =x
=2
ones digit=4(x)=4(2)=8
2+8=10
hence 28 is the number
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