Question

In a 2 digit number the units digit is four times the tens digit and the sum of the digits is 10. find the number​

Answer 1

Answer:

Let the tens digit be x and units digit be y

therefore the digit is xy

Unit digit is 4 times the tens digit

therefore y = 4x

4x - y = 0

The sum of both the digits is 10

Hence x + y = 10

Calculating (Adding) both the equations

5x = 10

x = 2

Solving the above (any one) equation, we get

y = 8

therefore the number is 28.

hope it helps you!

Answer 2

${\underline{\underline{\red{\sf{\hookrightarrow Answer:- }}}}}$

The Number is 82.

${\underline{\underline{\red{\sf{\hookrightarrow Step-by-step\: Explanation:- }}}}}$

Given that , in a 2 digit number the units digit is four times the tens digit and the sum of the digits is 10. So ,

Let us take ,

• $\sf \purple{Unit\:digit\:be\:x\:.}$
• $\sf \purple{Tens\: digit\:be\:y\:.}$

According to the first Condition ,

=> Unit digit = 4(Tens Digit ).

=> x = 4y. ..............(i)

According to the second Condition ,

=> Units digit + Tens Digit = 10.

=> x + y = 10.

=> 4y + y = 10.

=> 5y = 10.

=> y = 10/5.

=> y = 2.

Put this in (i) ,

=> x = 4y.

=> x = 4*2

=> x = 8.

Hence the value of x is 8 and y is 2 .

Hence the Number is 82.