In a 2 pole lap winding dc machine, the resistance of one conductor is 2 and the total number of conductors is 100. Find the total armature resistance
Answers
Total armature resistance is 50 Ω.
Explanation:
Total resistance depends upon no of parallel path. In lap winding parallel path is no of poles and here it is two. Half of conductor are in series i.e. 50 in series and rest of 50 in series and they are parallel together. 50 no 2Ω in series = 100Ω. When two such paths are parallel their equivalent will be 50 Ω.
Numerically it can also be stated:
Total armature resistance = X x Z / A^2
X = Resistance of one conductor
Z = Total number of conductors
A = No of parallel paths
Solution:
Total armature resistance = X x Z / A^2
Total armature resistance = 2 x 100 / 4 = 50 Ω
Thus total armature resistance is 50 Ω.
Also learn more
An electric bulb rated for 500W at 100V is used in a circuit having a 200V supply. The resistance R that must be kept in series with the bulb so that the bulb draws 500W is -
A) 30 ohm B) 5 ohm C) 20 ohm
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