Math, asked by ghaRakeshsrutiture, 1 year ago

In a 200m race of disabled children the speed of aarush,the winner,is 5m/sec more than that of barun ,the participant who came last .if barun reaches the finishing line 20 seconds after aarush then(a) find the speed of barun .(b) a group of students were having an argment varun say ,differently abled students as it slows their pace.' Remma said ;there would not be sufficient number of such students to be taught in a s

Answers

Answered by kvnmurty
1
Let the speed of Barun be  x  m/sec.
Speed of Aarush :   x+5  m/sec.

Timing of Aarush to complete 200m race = 200 / (x+5)  sec
Timing of Barun = 200/x  sec

Given     200/ x  = 20  +  200 / (x+5)   sec
               10 / x   -  10 /(x+5)    =  1
                50  =  x ( x+5)

        It is easy to get  x = 5 m/s  from the above equation.


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