Question

in a 2digit number, digits in units place is twice the digit in tens place. if 27is added to it, digits are reversed. find the number ​

Answer 1

Step-by-step explanation:

let the unit digit be x and the digit at tens place be y

then according to first condition;

x=2y

this is the required equation

and according to second condition;

10y+x+27=10x+y

solution

multiply the equation. 1by 9

then

9x-18y=0

-9x+9y=-27

on solving

y=3

putting the value of y in equal 1

we get

x=6

then the required no. is 36

Answer 2

Answer:

let the tens place be x and units place be y

ATQ,

x=2y.....(I)

original number is 10x+y

reversed number=10y+x

againATQ,

10y+x=10x+y+27

10y+x-10x+y=27

-9x+9y=27

9(-x+y)=27

-x+y=27/9

-x+y=3.......(ii)

-2y+y=3

y=3

x=2y

=2*3

=6

so the number will be 63 or 36.

HOPE IT HELPS!!!