In a 3.2 Kbp long piece of DNA, 840 adenine bases were found. What
would be the number of cytosine bases?
Answers
Answered by
0
Answer:
Total DNA = 3.2 Kbp = 3200 bp
Adenine = 820
According to Chargaff's rule
[A] = [T], [G] = [C]
So, Thymine = 820
Therefore, total A + T content = 820 + 820 = 1640
Also, A + T = 3200 - (G + C)
So, G + C content = 3200 - 1640 = 1560
So, cytosine
Answered by
0
Answer:
Answer:
Total DNA = 3.2 Kbp = 3200 bp
Adenine = 820
According to Chargaff's rule
[A] = [T], [G] = [C]
So, Thymine = 820
Therefore, total A + T content = 820 + 820 = 1640
Also, A + T = 3200 - (G + C)
So, G + C content = 3200 - 1640 = 1560
So, cytosine
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