Question

In a 3.6 kb long piece of DNA, 880 cytosine bases were found. The number of adenine bases would be​

Answer 1

Explanation:

One Kbp of DNA contains 1000 base pairs. So the total number of base pairs in 3.2kbp is (3.2X1000) 3200 bp. Out of which 820 base pairs are adenine so the number of thymine will also be 820 as number of adenine is equal to thymine according to chargoffs rule.

A total number of cytosine + guanosine will be 3200- 780X2= 1560. As the number of cytosine is equal to guanine so cytosine bases in the DNA can be calculated as 1560/2=780