In a 3-digit number, if the middle digit is equal to the sum of the other two digits, then it is a multiple of
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100a+10b+c+99=a+10b+c
a+b+c=10
a+c=b
Substitute a+c for b
a+c+a+c=20
2a+2c=10
a+c=5
Substitute b for a+c
b=5
100a+10(5)+c+99=+a+10(5)+100c
100a-a+50–50+c-100c=-99
99a-99c=-99
a-c=-1
a+c=5
2a+c-c=5–1
2a=4
a=2
2+c=5
c=3
The number has the digits, in order, 2, 5, and 3, so the number is 253
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