Question

In a 3 digit number the hundered digit is twice the tens digit while the unit digit is thrice the tens digit also the sum of its digit is thrice the tens digit. also the sum of its digits is 18. find the no.

Answer 1

Let the number be 100x+10y+z

So 100x+10y+z=18

But

100x=2x10y

100x=20y

Also

3x10y=z

30y=z

Hence

20y+10y+30y=18

60y=18

Y=3/10

So

X=20y/100

X=6

Similarly

Z=30y

Z=9

100x+10y+z

100X6

10X3/30

9

Hence number is 639

HOPE IT HELPS

MARK AS BRAINLIEST

Answer 2

Let the unit's place digit be x, the tenth place digit be y and the hundredth place digit be z of the three digit number

So the number will be $100z + 2y \times x$

Now given, sum of digits $= x + y + z = 12$

And $y=2x,z=3x$

$⇒x+2x+3x=12$

$⇒6x=12⇒x=2$

So $y=2x=4 and z=3x=6$

Hence the number is $=100z+10y+x=642$

So the reversed number is 246