Question

In a 3-digit number, the hundreds digit is twice the tens digit while the unit digit is twice the tens digit. The sum of the digits is 18. Find the number.​

Answer 1

Answer:

U=3t ; h=2t

U+t+h=18

∴t+3t+2t=18

6t=18

t=3

U=9

h=6

∴ no. is 639.

Step-by-step explanation:

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Answer 2

Please see the attachment or you can also see below the solution.

$❥{\underline{\boxed{\large{\rm{♕Solution♕}}}}}$

$\sf{Let\:the\:tens\:digit\:be\:x}$

$\sf{Then,\: hundreds=2x}$

$\sf{And\:units\:digit=3x}$

$\sf{ATQ,}$$\sf{2x+x+3x=18}$

$\sf{6x=18}$

$\sf{x=3}$

So, tens digit =3

Hundreds Digit=6

Units digit = 9

So, required number= 639