In a 3-digit number unit digits ten digit are in the ratio 1:2:3 . if the difference of the original number and the number obtained by reversing the digit is 594 . then find the number
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Let the digits of the number be y, 2y,3y
Number = 100(y)+10(2y)+3y
New number = 100(3y)+10(2y)+y
As per condition
The number is 100(3)+10(6)+3(3)
=369
Number = 100(y)+10(2y)+3y
New number = 100(3y)+10(2y)+y
As per condition
The number is 100(3)+10(6)+3(3)
=369
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