Question

In a 3-digit number unit digits ten digit are in the ratio 1:2:3 . if the difference of the original number and the number obtained by reversing the digit is 594 . then find the number

Answer 1

Let the digits of the number be y, 2y,3y
Number = 100(y)+10(2y)+3y
New number = 100(3y)+10(2y)+y
As per condition
$300y + 20y + y - 100y - 20y - 3y = 594 \\ 198y = 594 \\ y = 3$
The number is 100(3)+10(6)+3(3)
=369