Question

In a 3-digit number unit's digit is 2 less than hundred's digit and hundred's digit is 3 less than the ten's digit. If the sum of the original number and number obtained by reversing the digits is 968, find the number.​

Answer 1

Answer:

So the three digit number must be 639.

Step-by-step explanation:

The number is 639.

In a 3-digit number,

Like this one: 100a+10b+c

the hundreds digit is twice the tens digit

So a=2b. That works for me.

while the units digit is thrice the tens digit.

Okay, so c=3b. Sounds good.

Also, the sum of its digits is 18.

I believe you are suggesting that a+b+c=18. Sure, okay

What's the number?

Well, we'll start with the sum of the digits, and replace with what is given. So:

a+b+c=18

2b+b+3b=18

6b/6=18/6

b=3

Now that we know what the tens digit (b) is, the remaining digits are easy enough.

a=2b, so a=6

c=3b, so c=9

So the three digit number must be 639.

So the three digit number must be 639.