Question

In a 3-digit number, unit' s digit is one more than hundred' s digit and ten' s digit is one less than the hundred' s digit. If the sum of the original 3-digit number and numbers obtained by changing the order of digits cyclically is 2664, find the number.​

Answer 1

Answer:

879

Step-by-step explanation:

Let hundred digit =x  

ten digit =x−1

unit digit =x−1

First form of Number =100×x+100(x−1)+x+1

=111x−9

Second form of Number =(x+1)100+x×10+x−1

=111x+99

third form of number =(x−1)100+(x+1)10+x

=111x−90

So 111x−9+111x+99+111x−90=2664

111x=2664

x=8

So the number 8×100+7×10+9

=879

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Answer 2

Let hundred digit =x

ten digit =x−1

unit digit =x−1

First form of Number =100×x+100(x−1)+x+1

=111x−9

Second form of Number =(x+1)100+x×10+x−1

=111x+99

third form of number =(x−1)100+(x+1)10+x

=111x−90

So 111x−9+111x+99+111x−90=2664

111x=2664

x=8

So the number 8×100+7×10+9

=879