Question

in a 3-digit number, unit's, ten's and hundred's digit are in the ratio 1:2:3. if the difference of original number obtained on reversing is 396, find the number​

Answer 1

Answer:

ATQ

let a = X

b = 2x

c = 3x

now , original number = 100c +10b +a.

Reversing the digit we get

= 100a + 10b +c

Original- reverse = 396

Therefore

100c + 10b +a - ( 100a + 10b +c) = 396

100c + 10b + a - 100a - 10b - c = 396

100c -c + 10b -10b + a -100a = 396

99c -99a = 396

c-a = 396/99

c - a = 4

now put the value of c and a

3x-x = 4

X = 4/2

X = 2

Therefore numbers are

X = 2 = a.

b = 2x = 2×2 = 4

c = 3x = 3×2 = 6

Thus original number

= 100c + 10b +a

= 100× 6 + 10×4 + 2

= 600 +40+2

642

Answer = 642