Question

In a 3 digit number , units digit is one more than the hundred digit and

Answer 1

Answer:

Step-by-step explanation:

Complete question please

Answer 2

The no is 879

let hundreds digit=x

thus tens digit=x-1

ones digit=x+1

the first form of our no. is x*100+(x-1)10+(x+1)

                                       =111x-9   (value no.1)

second form is

(x+1)100+x*10+(x-1)

= 111x+99       (value no 2)

third form is

(x-1)100+(x+1)10+(x)

=111x-90       (value no 3)

these three values add up to 2664

111x-9+111x+99+111x-90=2664

3(111x)=2664

111x=888

x=8

therefore our no is 8*100+(8-1)*10+(8+1)

                              =800+70+9

                              =879