in a 34g of NH3 gas sample find: i) number of molecules present ii) number of H-atoms present iii)volume occupied (Atomic masses of N is 14g and H is 1g)
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hi there.
atomic wt of NH3 = 14+3=17 g
number of moles in 17g is 1 mole
number if moles in 34 g will be 1×2=2 moles.
ii) in 17g 1 atoms is present
hence in 34 g, 2 ×6.023×10 •23atoms
iii). volume occupied by 17 g is 22.4 L at stp
hence at 34 g it will be 22.4×2=44.8L.
i hope this helps.
regards
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