In a 35 Ibs mixture,the percent of quinine is 60%.how much pure quinine should be added to the mixture so that the adulteration is 35%of the total?
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Quantity in the mixture =35 lb
Quantity of quinine in the mixture =35*60/100=21lb
Quantity of adulteration in the mixture = 35-21=14lb
now, supose x lb of pure quinine is added in the mixture so that the ratio of pure quinine and the aduterant becomes 65:35
=>21+x=65*14/35=26lb
x=26-21=5lb
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