Math, asked by agilandon4141, 1 month ago

In a 35 Ibs mixture,the percent of quinine is 60%.how much pure quinine should be added to the mixture so that the adulteration is 35%of the total?

Answers

Answered by charyarujula2510
0

Quantity in the mixture =35 lb

Quantity of quinine in the mixture =35*60/100=21lb

Quantity of adulteration in the mixture = 35-21=14lb

now, supose x lb of pure quinine is added in the mixture so that the ratio of pure quinine and the aduterant becomes 65:35

=>21+x=65*14/35=26lb

x=26-21=5lb

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