In (a + 3a²b + 3ab² + b') + a + b the quotient is:
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(a+3a²b+ 3ab² + b ) +a+b
= a+a + 3a²b + 3ab² +b+b
=2a + 3a²b + 3ab² + 2b
=2a+3ab(a²+b²) +2b
Ans - 2a+3ab(a²+b²) + 2b
Step-by-step explanation:
- First we will sort out the similar variable i.e a+a and b+b , then we will add a+a which is 2a and b+b which is 2b
- Then we will take 3ab common and write a²+b² in bracket
Hope this helps you
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