Question

In a 3digit number,unit's digit , ten's digit and hundred's digit are in the ratio 1:2:3 . If the difference of the original number and the number obtained by reversing the digits is 594 , find the number​

Answer 1

3 digit number xyz can be written as 100x+10y+z

Let numbers be y,2y,3y

[(100×3y)+(10×2y)+y]-[(100y)+(10×2y)+3y]=594

solving y=3

hence number is 369