in a 5 digit number, 3 pairs of sum is 11 each.last digit is 3 times first one,3rd digit is 3 less than 2nd, 4th digit is 4 more than the second one. find the number.
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the require number be d1d2d3d4d5 Given d5=3d1 d3=d2-3 d4=d2+4 since sum of pair of digits=11 consider d3+d4=11 d2-3+d2+4=11 => d2=5 d3=d2-3 d3=5-3 d3=2 d4=d2+4=5+4 d4=9 hence require number = __529__ here 9+2=11 now we have think of a number which should be added to five to get 11 5+6=11 hence the last number is 6 since d5=3d1 ∴d1=2 hence the ans is 25296
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Answer:
25296
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