Question

In a 50 litre mixture of water and milk, water is only 20%. The milkman gives '10 litres' of this mixture to a customer and then he adds up 10 liters of pure water in the remaining mixture. The percentage of water in the final mixture is:

Answer 1

Step-by-step explanation:

20% of 10 = 1/5 of 10 = 2 L water

12 litre water + 8 Litre milk in final mixture .

(12/20)*100 = (3/5)*100

= 20*3 = 60 % water

Answer 2

The percentage of water in the final mixture is 60%.

Step-by-step explanation:

Given:

In a 50 litre mixture of water and milk, water is only 20%.

The milkman gives '10 litres' of this mixture to a customer and then he adds up 10 liters of pure water in the remaining mixture.

The percentage of water in the final mixture is:

Solution:

20% of 10 = $\frac{1}{5}$ of 10  

$\frac{12}{20} \times 100$ = $\frac{3}{5} \times 100$

= 20$\times$3 = 60%

The percentage of water in the final mixture is 60%.

To know more:

In three vessels, the ratio of water and milk is 6 : 7, 5 : 9 and 8 : 7, respectively. If the mixture of the three vessels is mixed, then what will be the ratio of water and milk?

(a) 2431 : 3781

(b) 3691 : 4499

(c) 4381 : 5469

(d) 5469 : 3691

(e) None of the above

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