In a 50 litres mixture of milk and water volume of water is 60% total mixture. A few litres of mixture is released and an equal amount of water is added and this process is reapeted once again. If volume of water was 15% in final mixture then how many litres of mixture released
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Answer:
Quantity of the original solution = x litre
Content of milk in x litre solution = 0•6x litre
Content of water in the solution = 0•4x litre
By adding 5 litre water the content = 0•4x + 5 litre
The total quantity of original solution becomes now = x + 5 litre
So 0•6x/(x + 5) = 0•5
0•6x = 0•5x + 2•5
0•1x = 2•5
x = 25/1 = 25 litre
The quantity of the original solution =25 litre
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In a 50 litres mixture of milk and water volume of water is 60% total mixture. A few litres of mixture is released and an equal amount of water is added and this process is reapeted once again. If volume of water was 15% in final mixture
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