Question

In a 500 mL capacity vessel 0.2 mole of COCI,
At equilibrium, it contains 0.2 mole of COCI,
and 0.1 mole of each of CO and Cl.. The equilib-
rium constant K for reaction, CO +
C1=COCI, is:
a) 5
b) 10
c) 15
d) 20​

Answer 1

Answer:

c. 15

Explanation:

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Answer 2

Correct  Question:

In a 500 mL capacity vessel, CO and Cl₂are mixed to form COCl₂

At equilibrium, it contains 0.2 moles of COCI, and 0.1 moles of each of CO and Cl₂.The equilibrium constant K for reaction, CO + C1₂ →COCI₂ is:

Given:

• The volume of the solution = 500 ml = 0.5 L

Moles of reactants and products present at equilibrium:

• CO = Cl₂ = 0.1 moles
• COCl₂ = 0.2 moles

To find:

• Equilibrium constant

Formula:

For a given reaction ,

• aA + bB $\rightleftharpoons$ cC + dD

The equilibrium constant is given by,

$\to \sf{K_c= \dfrac{[C]^c .[D]^d}{[A]^a.[B]^b}}$

• K꜀ = equilibrium constants
• a,b,c,d = stotiometric coefficients
• A,B,C,D = concentration in mol/L

Solution:

Given reaction,

CO + C1₂ $\rightleftharpoons$ COCI₂

The equilibrium constant is given by,

$\to \sf{K_c= \dfrac{[COCl_2]}{[CO].[Cl_2]}}$

Here,

• [COCI₂] = 0.2/0.5 = 0.4
• [CO] = [Cl₂] = 0.1/0.5 = 0.2

Now let's substitute these values in the above equation,

$\to \sf{K_c= \dfrac{0.4}{0.2 \times 0.2}}$

$\to \sf{K_c= \dfrac{0.4}{0.04}}$

$\to \sf{K_c= 10}$

The equilibrium constant for the reaction is 10.