Math, asked by rahulnaik98127, 9 months ago

In a 500m race, B gives A a start of 160m.
The ratio of the speeds of A and B is 2:3.
What was the distance by which the
winner beat the loser?​

Answers

Answered by ihrishi
0

Step-by-step explanation:

A will have to cover the distance 500-160=340m

therefore 2/3 =340/x

x = 340* (3/2)

x= 510

so 500 - 510 = - 10

B wins by 10 m.

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