Question

In a 51 s interval, 480 hailstones strike a glass window of area 0.883 m2 at an angle 48◦ to the window surface. Each hailstone has a mass of 7 g and speed of 10.5 m/s. If the collisions are elastic, find the average force on the window. Answer in units of N.

Answer 1

Answer:

Force due to hailstones on the window is 1.03 N

Explanation:

As we know that the rate of change in momentum of hailstones must be the force applied by them

Now we have

$F = \frac{dP}{dt}$

so we have

$F = \frac{dN}{dt}(2mvsin\theta)$

here we know that

$\frac{dN}[dt} = \frac{480}{51}$

$F = \frac{480}{51} 2(0.007)(10.5)sin48$

$F = 1.03 N$

#Learn

Topic : Newton's II law

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