Question

In a 720 ml liquid, milk and water have a ratio of 7: 2. How much water is added to make the mixture a ratio of 7:3?​

Answer 1

$\huge{ \red{ \underline{ \underline{ \mathfrak{ \color{orange}{answer}}}}}}$

$\tt \: \blue{80ml} \: of \: water \: is \: added \: to \: make \: the \: new \: ratio$

$\huge{ \color{aqua}{ \underbrace{ \underline{ \color{lime}{ \mathbb{✯꧁᭄⋆SoLuTiOn⋆᭄꧂✯ }}}}}}$

$\tt \: total \: amount \: of \: liquid = 720ml$

$\tt \: let \: the \: ratio \: be \: 7x \: and \: 2x$

$\tt \: according \: to \: the \: question$

$\tt \to7x + 2x = 720$

$\tt \to9x = 720$

$\tt \to \: x = \frac{ \cancel{720}}{ \cancel9}$

$\tt \to \: x = 80$

Now,

$\tt \: in \: the \: ratio \: 7 \ratio2 \\ \tt \: milk = 7x=7(80) = 560ml \\ \tt \: water =2x= 2(80) = 160ml$

$\tt \: in \: the \: new \: ratio \:7 \ratio3$

$\tt \: milk = 7(80) = 560ml$

$\tt \: water =3(80) = 240ml$

$\tt \: added \: water = 240 - 160 = \red{80ml}$

$\tt \therefore80ml \: of \: water \: is \: added \:$