Question

In a A ABC, AB = 30 cm, BC = 26 cm and AC = 28
cm. Find the area of AABC

Answer 1

Answer:

Given,

ab=30cm bc=26cm ac=28cm

S=a+b+c/2

= 30+26+28/2

=84/2

=42

Area=

\sqrt{s(s - a)(s - b)(s - c) }

s(s−a)(s−b)(s−c)

=

\sqrt{42(42 - 30)(42 - 26)(42 - 28)}

42(42−30)(42−26)(42−28)

=

\sqrt{42 \times 12 \times 16 \times 14}

42×12×16×14

=

\sqrt{112896}

112896

= 336cm^{2}=336cm

2

Area of ∆ABC=1/2× base×height

84cm ^{2} = 1 \div 2 \times 28cm \times h84cm

2

=1÷2×28cm×h

h = (2 \times 84) \div 28cmh=(2×84)÷28cm

h = 168 \div 28h=168÷28

= 6=6

therefore altitude on Ac= 6cm

100℅sure answer

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