In a A ABC, if 3 ZA = 4ZB = 6 ZC, calculate the angles.
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Answer:
Step-by-step explanation:
Given:
ABC is a triangle.
3∠a=4∠b=6∠c
to find: ∠a
∠b
∠c
find: ∠a+∠b+∠c=180° (sum of all angles of triangle) ------(i)
3∠a =4∠b
3∠a= 4∠b
3∠a/4 = ∠b ------(ii)
3∠a=6∠c
3∠a/6= ∠c
∠a/2=∠c ------(iii)
from (i).....
∠a+∠b+∠c=180°
∠a+3∠a/4 +∠a/2 =180°
(4∠a+3∠a+2∠a)/4 = 180°
9∠a=180 ×4
∠a = 180×4/9
∠a = 80°
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