In a A ABC, ZB = 90°. If AB = 4cm and BC = 3cm, find the value of
sin A and tan c.
Answers
Answered by
3
Answer:
Step-by-step explanation:
In the triangle abc , ab =4cm and bc = 3cm
Then by pythagoras theorem
Ac^2 = bc square + ab square
Ac square =√25
That is =5
We got AC as 5 cm
Then sin A = opposite by hypotenuse
That is sin A= 3 / 5
Tan C = opposite by adjacent = 4/3
Answered by
1
Answer:
i have given the solution in the photo
Attachments:
Similar questions