In a A P 4th term and 8th term are in
the ratio 1:2 of the sum of 6th and 10th
term is 34 Find the
Arithemetic
Progression.
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Explanation:
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Answer:
T
n
=a+(n−1)d
T
4
+T
8
=24
a+3d+a+7d=24
a+5d=12...(1)
T
6
+T
10
=34
a+5d+a+9d=34
a+7d=17...(2)
(2)-(1) gives:
∴d=
2
5
From (1)
a=17−7d
a=17−7(
2
5
)
∴a=−
2
1
Explanation:
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