Math, asked by nayakkusadev, 7 months ago

In a A.P. t17 is 34. Find out S33​

Answers

Answered by pulakmath007
16

SOLUTION

GIVEN

In an AP

 \sf{ t_{17} = 34\: }

TO DETERMINE

 \sf{S_{33}}

CONCEPT TO BE IMPLEMENTED

If in an arithmetic progression

First term = a and Common difference = d

Then

1. The nth term of the progression is

 \sf{t_n  = a + (n - 1)d}

2. The sum of the first n terms

 \displaystyle \sf{S_n =  \frac{n}{2} \bigg[2a + (n - 1)d \bigg] }

EVALUATION

Here it is given that for an arithmetic progression

 \sf{ t_{17} = 34\: }

Let first term = a and common difference = d

 \sf{ t_{17} = 34\: }

 \implies \sf{a + (17 - 1)d = 34 \: }

 \implies \sf{a + 16d = 34 \: } \:  \:  \: ......(1)

Hence

 \displaystyle \sf{S_{33} =  \frac{33}{2} \bigg[2a + (33 - 1)d \bigg] }

 \displaystyle \sf{=  \frac{33}{2} \bigg[2a + 32d \bigg] }

 \displaystyle \sf{=  33 \bigg[a + 16d \bigg] }

 \sf{  = 33 \times 34\: } \:   \: (\: using \:  \: eqn. \: 1)

 =  \sf{1122}

━━━━━━━━━━━━━━━━

LEARN MORE FROM BRAINLY

find the 100th term of an AP

whose nth term is 3n+1

https://brainly.in/question/22293445

Similar questions