Question

= In a AABC, AB AB = BC, BC, ZB ZB = x° and ZA = (2x - 20°), then ZB is equal to (c) 44° (d) 64° - (a) 30° (b) 40°​

Answer 1

Answer:

From fig.,

In △ABC,

∵AB=BC

∴∠C=∠A=(2x−20)°(∵ angle oppsite to the equal sides are equal)

∠B=x°

As we know that sum of all interior angles of a triangle is 180°.

∴∠A+∠B+∠C=180°

⇒(2x−20)°+x°+(2x−20)°=180°

⇒(5x−40)°=180°

⇒5x=180°+40°

⇒x=

5

220

​

=44°

∴∠B=44°

Step-by-step explanation:

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Answer 2

Answer:

c) 44°

Step-by-step explanation:

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