In a AABC, AB = AC. If ZA = 80°, then the measure of B is
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Answer:
angle A =80°
given,AB=AC
angle B=angle c(by properties of isosceles triangle)
Now,let base angle of triangle be X
A/q
X+X+80°=180°
2X+80°=180°
2X=180°-80°
2X=100°
X=100°/2
X= 50°
Hence, angle B and angle C =50°each
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