Question

. In a AABC, AD bisects ZBAC and AD = DC. If ZBDA = 70°, calculate ZACD and ZABD.​

Answer 1

Answer:

75°

Step-by-step explanation:

Hence angle dac=angle dca =x(say)

we know that the exterior angle is equal to sum of its opposite interior angle

hence, angle ADB=angle (dac+dca)

70=x+ x

x=35

and angle bad=angle dac = 35°

Now, in triangle ABD we have

70°+35°+angle ABD=180°

angle ABD=180°-105°=75°  

Hence The measurement of angle ABD is 75°

please mark me brainiest