In a AABC. AD is the median through A and E is the mid-point of AD. BE produce meets
AC at F then AF- ?
A) / AC
B) AC
C) AC
D) none of these
O
A)
B)
O O
C)
O O
D)
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0
Answer:
produced meets AC in F, Prove that AF 1/3 AC. ... AD is the median of ΔABC and E is the midpoint of AD Through D ... By converse of midpoint theorem we have. F is ...
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