Question

In a AABC, DE || BC and AD = 3cm, DB = 5cm, AE = 6cm, then find the value of EC.
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Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

The answer to the given question is the value of EC is 10 cm.

Step-by-step explanation:

Given data :

In ∆ABC, DE II BC implies DE is parallel to BC.

The length of AD is 3 cm

The length of DB is 5 cm.

The length of AE is 6cm

To find :

The value of EC

Solution :

Is it given that the DE is parallel to BC?

In an ∆ ABC, draw a line DE parallel to BC.

D and E are the midpoints of AB and AC respectively.

The line splits the triangle into 2 parts, and four sides.

The value of 3 parts of the Triangle is given we have to find the fourth part.

This is obtained by

$\frac{AD}{DB} = \frac{AE}{EC}$

let the value of EC be x.

substitute all the values in the formula we get,

$\frac{3}{5} = \frac{6}{x}$

on cross multiplying, we get the values as

$3x = 30 \\ x = \frac{30}{3} \\ x = 10$

The value of x is found as 10.

Therefore, the value of EC is obtained as 10cm.

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