In a AABC. if AB + BC = 10 cm, BC + CA= 12
cm, CA+AB = 16 cm, then the perimeter of
the triangle is
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AB + BC = 10
BC + CA = 12
CA + AB = 16
2(AB + BC + CA) = 38
AB + BC + CA = 19 cm
∴ Perimeter = 19 cm
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