In a AABC, if <A = 45°
and <B = 70°, then find
the shortest side of the
triangle?
Answers
Answered by
0
Answer:
<A
PLEASE MAKE ME AS BRANILIENST
Step-by-step explanation:
- <A = 45°
- <B = 70°
- <C = ? = 65⁰
- <A + <B + <C = 180⁰
} Angle sum property of a ∆le
- 45⁰+ 70⁰+ <C = 180
- <C = 180⁰ - 115⁰
- = 65⁰
So, the smallest angle is <A which is 45⁰
HOPE IT HELP'S YOU
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